Figure 4From: A scalable method for identifying frequent subtrees in sets of large phylogenetic treesThe set of input trees T 1 , T 2 , T 3 and the set of all nine potential seeds S 1 , S 2 … S 9 when the seed characteristics are set to k  = 3 and c  = 1. All the potential seeds have three taxa as k = 3. We need one contraction from the input tree to obtain each seed. S1 has frequency 1.0 as it is present in T1, T2 and T3. Seed S2 has frequency ∼0.67 as it is present in T1 and T2. Remaining seeds have frequency ∼0.33 as each appears in only one of the three trees.Back to article page