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Table 3 Results of fitting a parametric survival regression using the logistic distribution to the unique URLs.

From: A cross disciplinary study of link decay and the effectiveness of mitigation techniques

Variable

Value

p

5%

95%

(Intercept)

5.22

3.3E-30

4.46

5.97

Log2(URL published)

3.57

1.4E-17

2.88

4.25

depth

-1.46

7.0E-32

-1.66

-1.25

Log2(TimesCited + 1)

0.25

2.8E-04

0.13

0.36

Funding text present

3.43

2.8E-11

2.59

4.28

Domain

au

4.53

1.5E-04

2.56

6.49

be

3.31

1.9E-02

0.99

5.64

ca

4.88

1.7E-06

3.20

6.56

ch

6.45

7.2E-08

4.48

8.42

cn

1.50

1.3E-01

-0.13

3.13

com

6.02

2.2E-18

4.89

7.16

de

5.74

6.1E-16

4.57

6.91

dk

7.66

5.7E-07

5.14

10.18

edu

3.77

1.6E-13

2.93

4.61

es

3.05

5.4E-03

1.25

4.85

fr

3.65

6.6E-07

2.44

4.85

gov

5.51

1.2E-15

4.38

6.64

il

5.92

3.6E-04

3.19

8.65

in

4.78

2.2E-04

2.65

6.91

it

5.51

1.4E-08

3.91

7.11

jp

5.07

8.0E-09

3.62

6.51

kr

-3.35

2.0E-02

-5.73

-0.97

net

7.01

4.2E-11

5.26

8.76

nl

6.78

1.1E-06

4.49

9.07

org

8.10

2.4E-36

7.04

9.16

ru

3.90

2.3E-03

1.80

6.01

se

1.71

2.4E-01

-0.69

4.12

tw

1.64

1.7E-01

-0.33

3.61

uk

4.49

4.2E-12

3.42

5.56

Source

Bioinformatics

-2.04

5.7E-03

-3.25

-0.83

BMC Bioinformatics

2.69

3.9E-05

1.62

3.77

BMC Genomics

0.88

4.7E-01

-1.13

2.89

Comp. Physics Comm.

-4.00

3.0E-05

-5.57

-2.42

Genome Research

0.56

7.1E-01

-1.92

3.04

Nucleic Acids Research

1.28

8.6E-04

0.65

1.91

PLoS ONE

-0.39

8.0E-01

-2.95

2.18

Zoological Studies

16.42

2.2E-15

13.01

19.83

  1. Positive numbers indicate longer median lifetimes. Much like a logistic model, coefficients can be added to the intercept value (after multiplying in the case of numeric predictors) to obtain a median lifetime. For example, the median expected lifetime for a URL published once, with depth 0, whose publishing article had 1 citation, no funding text, domain au and published in a Journal not listed (ie- in the default) would be: (Intercept) 5.22 + Log2(1)*3.57 + 0*-1.46 + Log2(1+1)*0.25 + 0*3.43 + 4.53 = 10 years