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Table 2 Conditions required for a 4-state Markovian process to be lumpable (in terms of s and π), and transformations to obtain π ˜ and s ˜ such that the lumpability holds.

From: Statistical tests to identify appropriate types of nucleotide sequence recoding in molecular phylogenetics

S

Lumpability conditions

( π ˜ , s ˜ )

{{A, G}, C, T}

s12 = s23

s14 = s34

s ˜ 13 = s ˜ 23 = ( ŝ 13 + ŝ 23 ) / 2

s ˜ 14 = s ˜ 34 = ( ŝ 14 + ŝ 34 ) / 2

{A, G, {C, T}}

s12 = s14

s23 = s34

s ˜ 12 = s ˜ 14 = ( ŝ 12 + ŝ 14 ) / 2

s ˜ 23 = s ˜ 34 = ( ŝ 23 + ŝ 34 ) / 2

{A, {C, G}, T}

s12 = s13

s24 = s34

s ˜ 12 = s ˜ 13 = ( ŝ 12 + ŝ 13 ) / 2

s ˜ 24 = s ˜ 34 = ( ŝ 24 + ŝ 34 ) / 2

{C, G, {A, T}}

s12 = s24

s13 = s34

s ˜ 12 = s ˜ 24 = ( ŝ 12 + ŝ 24 ) / 2

s ˜ 13 = s ˜ 34 = ( ŝ 13 + ŝ 34 ) / 2

{{A, C}, G, T}

s13 = s23

s14 = s24

s ˜ 13 = s ˜ 23 = ( ŝ 13 + ŝ 23 ) / 2

s ˜ 14 = s ˜ 24 = ( ŝ 14 + ŝ 24 ) / 2

{A, C, {G, T}}

s13 = s14

s12 = s13

s ˜ 13 = s ˜ 14 = ( ŝ 13 + ŝ 14 ) / 2

s ˜ 23 = s ˜ 24 = ( ŝ 23 + ŝ 24 ) / 2

{A, {C, G, T}}

s12 = s13

s13 = s14

s ˜ 12 = s ˜ 13 = s ˜ 14 = ( ŝ 12 + ŝ 13 + ŝ 14 ) / 3

{C, {A, G, T}}

s12 = s23

s23 = s24

s ˜ 12 = s ˜ 23 = s ˜ 24 = ( ŝ 12 + ŝ 23 + ŝ 24 ) / 3

{G, {A, C, T}}

s13 = s23

s23 = s34

s ˜ 13 = s ˜ 23 = s ˜ 34 = ( ŝ 13 + ŝ 23 + ŝ 34 ) / 3

{T, {A, C, G}}

s14 = s24

s24 = s34

s ˜ 14 = s ˜ 24 = s ˜ 34 = ( ŝ 14 + ŝ 24 + ŝ 34 ) / 3

{{A, G}, {C, T}}

s12π2 + s14π4 = s23π2+ s34π4

s12π1 + s23π3 = s14π1+ s34π3

s ˜ 23 = s ˜ 12 ( π ^ 2 π ^ 3 - π ^ 1 π ^ 4 ) + s ˜ 14 π ^ 4 ( π ^ 1 + π ^ 3 ) π ^ 3 ( π ^ 2 + π ^ 4 )

s ˜ 34 = s ˜ 12 π ^ 1 + s ˜ 23 π ^ 3 - s ˜ 14 π ^ 1 π ^ 3

{{A, T}, {C, G}}

s12π2 + s13π3 = s24π2+ s34π3

s12π1 + s24π4 = s13π1+ s34π4

s ˜ 13 = s ˜ 12 ( π ^ 1 π ^ 3 - π ^ 2 π ^ 4 ) + s ˜ 24 π ^ 4 ( π ^ 2 + π ^ 3 ) π ^ 3 ( π ^ 1 + π ^ 4 )

s ˜ 34 = s ˜ 12 π ^ 2 + s ˜ 13 π ^ 3 - s ˜ 24 π ^ 2 π ^ 3

{{A, C}, {G, T}}

s13π3 + s14π4 = s23π3 + s24π4

s13π1 + s23π2 = s14π1 + s24π4

s ˜ 23 = s ˜ 13 ( π ^ 2 π ^ 3 - π ^ 1 π ^ 4 ) + s ˜ 14 π ^ 4 ( π ^ 1 + π ^ 2 ) π ^ 2 ( π ^ 3 + π ^ 4 )

s ˜ 24 = s ˜ 13 π ^ 1 + s ˜ 23 π ^ 2 - s ˜ 14 π ^ 1 π ^ 2