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Table 5 Comparing the data structures to compute the goProfiles test and the one based on enrichment contingency tables.

From: An equivalence test between features lists, based on the Sorensen–Dice index and the joint frequencies of GO term enrichment

 

Non-enriched in both lists

Enriched only in list 1

Enriched only in list 2

Enriched in both lists

GO term number

1

\(\cdots\)

\(a = n_{00}\)

\(a + 1\)

\(\cdots\)

\(b = a + n_{10}\) \(= n_{.0}\)

\(b + 1\)

\(\cdots\)

\(c = b + n_{01}\)

\(c + 1\)

\(\cdots\)

\(c + n_{11}\) \(= n\)

Annotation frequency in gene list 1

\(F_{11}\)

\(\cdots\)

\(F_{1a}\)

\(F_{1(a + 1)}\)

\(\cdots\)

\(F_{1b}\)

\(F_{1(b+1)}\)

\(\cdots\)

\(F_{1c}\)

\(F_{1(c+1)}\)

\(\cdots\)

\(F_{1n}\)

Annotation frequency in gene list 2

\(F_{21}\)

\(\cdots\)

\(F_{2a}\)

\(F_{2(a + 1)}\)

\(\cdots\)

\(F_{2b}\)

\(F_{2(b+1)}\)

\(\cdots\)

\(F_{2c}\)

\(F_{2(c+1)}\)

\(\cdots\)

\(F_{2n}\)

Enrichment in list 1

0

\(\cdots\)

0

1

\(\cdots\)

1

0

\(\cdots\)

0

1

\(\cdots\)

1

Enrichment in list 2

0

\(\cdots\)

0

0

\(\cdots\)

0

1

\(\cdots\)

1

1

\(\cdots\)

1

  1. In the latter test, the annotation frequencies are substituted by 0 and 1 (i.e., “non-enriched” and “enriched” GO term.) and if the test is based on the Sorensen–Dice similarity, the first set of GO terms (non-enriched in both lists) is ignored. The GO terms are arbitrarily ordered: from left to right, first there are all those non-enriched in both lists (\(n_{00}\) in total), next those enriched in the first list but not in the second one (\(n_{10}\)), then those enriched in the second list but not in the first (\(n_{01}\)) and finally those GO terms enriched in both lists (\(n_{11}\))