Figure 5From: SABERTOOTH: protein structural alignment based on a vectorial structure representationFits of Mean PSI and Standard Deviation for the Z -score. The upper figure shows the log-log scatter plot of the PSI versus the length of the shorter chain for the Z-score set together with the power-law fit for the mean PSI that resulted in ⟨PSI⟩ = 494·min (N1, N2)-0.712. The lower plot shows the log-linear plot of binned PSIs' standard deviations. The exponential fit resulted in σPSI = 25.00 - [3.896·log (min (N1,N2))].Back to article page