From: Sparse multiple co-Inertia analysis with application to integrative analysis of multi -Omics data
nen=(3,4,5) | ||
---|---|---|
 | nel=10 | nel=20 |
σ2=1.2 | scenario 1 | scenario 2 |
 | \(\boldsymbol {a}_{1}=((\boldsymbol {1}_{3}, \boldsymbol {0}_{27})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{1}=((\boldsymbol {1}_{3}, \boldsymbol {0}_{27})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
 | \(\boldsymbol {a}_{2}=((\boldsymbol {1}_{4}, \boldsymbol {0}_{36})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{2}=((\boldsymbol {1}_{4}, \boldsymbol {0}_{36})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
 | \(\boldsymbol {a}_{3}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{45})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{3}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{45})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
σ2=2.5 | scenario 3 | scenario 4 |
 | \(\boldsymbol {a}_{1}=((\boldsymbol {1}_{3}, \boldsymbol {0}_{27})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{1}=((\boldsymbol {1}_{3}, \boldsymbol {0}_{27})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
 | \(\boldsymbol {a}_{2}=((\boldsymbol {1}_{4}, \boldsymbol {0}_{36})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{2}=((\boldsymbol {1}_{4}, \boldsymbol {0}_{36})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
 | \(\boldsymbol {a}_{3}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{45})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{3}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{45})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
nen=(5,5,5) | ||
 | nel=10 | nel=20 |
σ2=1.2 | scenario 5 | scenario 6 |
 | \(\boldsymbol {a}_{1}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{25})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{1}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{25})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
 | \(\boldsymbol {a}_{2}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{35})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{2}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{35})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
 | \(\boldsymbol {a}_{3}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{45})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{3}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{45})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
σ2=2.5 | scenario 7 | scenario 8 |
 | \(\boldsymbol {a}_{1}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{25})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{1}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{25})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
 | \(\boldsymbol {a}_{2}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{35})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{2}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{35})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |
 | \(\boldsymbol {a}_{3}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{45})^{\intercal } \bigotimes \boldsymbol {1}_{10})\) | \(\boldsymbol {a}_{3}=((\boldsymbol {1}_{5}, \boldsymbol {0}_{45})^{\intercal } \bigotimes \boldsymbol {1}_{20})\) |