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Table 1 Low-dimensional setting of effect vectors in Scenario 1

From: Multiple phenotype association tests based on sliced inverse regression

Case 1

k=5, q=5

\(\varvec{\beta }_{3}=(1.10,1.10,1.10,1.10,1.10)\)

\(\varvec{\beta }_{4}=(0.00,0.02,0.00,0.00,0.00)\)

Case 2

k=5, q=10

\(\varvec{\beta }_{3}=(1.10,1.10,1.10,1.10,1.10,0.00,0.00,0.00,0.00,0.00)\)

\(\varvec{\beta }_{4}=(0.00,0.02,0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00)\)

Case 3

k=10, q=5

\(\varvec{\beta }_{3}=(1.10,1.10,1.10,1.10,1.10)\)

\(\varvec{\beta }_{4}=(0.00,0.02,0.00,0.00,0.00)\)

Case 4

k=10, q=10

\(\varvec{\beta }_{3}=(1.10,-1.10,1.10,-1.10,1.10,0.00,0.00,0.00,0.00,0.00)\)

\(\varvec{\beta }_{4}=(0.00,0.02,0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00)\)

  1. \(*\) The default value of other effect vectors \({\varvec{\beta }_j}\)’s are \({\textbf{0}}\)